Table of Contents
A repeated measures ANOVA in SAS can be performed by using PROC GLM. This procedure allows for the analysis of data from a single group of participants over multiple trials or measurements. The repeated measures ANOVA takes the form of a linear model and requires the specification of the dependent variable, the within-subject factor, and the model statement. The output from the procedure provides information about the main effect of the within-subject factor and any interactions between the within-subject factor and other effects. With this output, you can determine whether the differences between each level of the within-subject factor are statistically significant.
A repeated measures ANOVA is used to determine whether or not there is a statistically significant difference between the means of three or more groups in which the same subjects show up in each group.
This tutorial provides a step-by-step example of how to perform a repeated measures ANOVA in SAS.
Step 1: Create the Data
Suppose a researcher want to know if four different drugs lead to different reaction times. To test this, he measures the reaction time of five patients on the four different drugs.
The reaction times are shown below:
We can use the following code to create this dataset in SAS:
/*create dataset*/
data my_data;
input Subject Drug Value;
datalines;
1 1 30
1 2 28
1 3 16
1 4 34
2 1 14
2 2 18
2 3 10
2 4 22
3 1 24
3 2 20
3 3 18
3 4 30
4 1 38
4 2 34
4 3 20
4 4 44
5 1 26
5 2 28
5 3 14
5 4 30
;
run;
Step 2: Perform the Repeated Measures ANOVA
Next, we’ll use proc glm to perform the repeated measures ANOVA:
/*perform repeated measures ANOVA*/
proc glm data=my_data;
class Subject Drug;
model Value = Subject Drug;
run;
Step 3: Interpret the Results
We can analyze the ANOVA table in the output:
The only value we’re interested in is the F value and corresponding p-value for Drug since we want to know if the four different drugs lead to different reaction times.
From the output we can see:
- The F Value for Drug: 24.76
- The p-value for Drug: <.0001
- H0: All group means are equal.
- HA: At least one group mean is different from the rest.
Since the p-value for Drug (<.0001) is less than α = .05, we reject the null hypothesis.
This means we have sufficient evidence to say that the mean response time is not equal among the four different drugs.
The following tutorials provide additional information about repeated measures ANOVAs: