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We can use the following process to find the probability that a normally distributed X takes on a certain value, given a mean and standard deviation:
Step 1: Find the z-score.
A z-score tells you how many standard deviations away an individual data value falls from the mean. It is calculated as:
z-score = (x – μ) / σ
where:
- x: individual data value
- μ: population mean
- σ: population standard deviation
Step 2: Find the probability that corresponds to the z-score.
Once we’ve calculated the z-score, we can look up the probability that corresponds to it in the .
The following examples show how to use this process in different scenarios.
Example 1: Probability Less Than a Certain Value
The scores on a certain test are normally distributed with mean μ = 82 and standard deviation σ = 8. What is the probability that a given student scores less than 84 on the test?
Step 1: Find the z-score.
First, we will find the z-score associated with a score of 84:
z-score = (x – μ) / σ = (84 – 82) / 8 = 2 / 8 = 0.25
Step 2: Use the z-table to find the corresponding probability.
Next, we will look up the value 0.25 in the :
Example 2: Probability Greater Than a Certain Value
The height of a certain species of penguin is normally distributed with a mean of μ = 30 inches and a standard deviation of σ = 4 inches. If we randomly select a penguin, what is the probability that it is greater than 28 inches tall?
Step 1: Find the z-score.
First, we will find the z-score associated with a height of 28 inches.
z-score = (x – μ) / σ = (28 – 30) / 4 = -2 / 4 = -.5
Step 2: Use the z-table to find the corresponding probability.
Next, we will look up the value -0.5 in the :
The value that corresponds to a z-score of -0.5 is .3085. This represents the probability that a penguin is less than 28 inches tall.
However, since we want to know the probability that a penguin will have a height greater than 28 inches, we need to subtract this probability from 1.
Thus, the probability that a penguin will have a height greater than 28 inches is: 1 – .3085 = 0.6915.
Example 3: Probability Between Two Values
The weight of a certain species of turtle is normally distributed with a mean of μ = 400 pounds and a standard deviation of σ = 25 pounds. If we randomly select a turtle, what is the probability that it weighs between 410 and 425 pounds?
Step 1: Find the z-scores.
First, we will find the z-scores associated with 410 pounds and 425 pounds
z-score of 410 = (x – μ) / σ = (410 – 400) / 25 = 10 / 25 = 0.4
z-score of 425 = (x – μ) / σ = (425 – 400) / 25 = 25 / 25 = 1
Step 2: Use the z-table to find the corresponding probability.
First, we will look up the value 0.4 in the :
Then, we will look up the value 1 in the :
Then we will subtract the smaller value from the larger value: 0.8413 – 0.6554 = 0.1859.
Thus, the probability that a randomly selected turtle weighs between 410 pounds and 425 pounds is 18.59%.